E 10-6
|
Depreciation Expense Per Year |
|||
|
Year |
Straight-Line |
Units-of-Production |
Double-Declining-Balance |
|
20X1 |
$ 3,000 |
$ 4,080 |
$ 7,500 |
|
20X2 |
3,000 |
3,360 |
3,750 |
|
20X3 |
3,000 |
2,160 |
375 |
|
20X4 |
3,000 |
2,400 |
375 |
|
|
$12,000 |
$12,000 |
$12,000 |
__________
Computations:
Straight-line: ($15,000
! $3,000) ) 4 = $3,000 per year.Units-of-production: ($15,000
! $3,000) ) 100,000 miles = $.12 per mile;34,000 ´ $.12 = $4,080; 28,000 ´ $.12 = $3,360; 18,000 ´ $.12 = $2,160;
20,000 ´ $.12 = $2,400.
Double-declining-balance: $15,000 ´ (1/4 ´ 2) = $7,500;
($15,000
! $7,500) ´ 2/4 = $3,750; ($15,000 ! $7,500 ! $3,750) =$3,750
! $3,000 residual value = $750 ) 2 = $375.The units-of-production method tracks the wear and tear on the truck most closely.
For income-tax purposes, the double-declining-balance method is best because it provides the most depreciation and thus the largest tax deductions in the early life of the asset. The company can invest the tax savings to earn a return on the investment.
(15-20 min.)
E 10-7MACRS depreciation method for income tax:
Double-declining-balance
|
|
Double- Declining- Balance |
Straight- Line |
|
Year 1: |
|
|
|
$165,000 ´ 2/7 |
$47,143 |
|
|
($165,000 ! $16,500) ) 7 |
|
$21,214 |
|
Year 2: |
|
|
|
($165,000 ! $47,143) ´ 2/7 |
33,673 |
|
|
($165,000 ! $16,500) ) 7 |
______ |
21,214 |
|
Total |
$80,816 |
$42,428 |
|
Extra cash to invest with DDB |
|
|
|
($80,816 ! $42,428) |
$38,388 |
|
__________
Note: This solution ignores the half-year convention of MACRS depreciation.
(10-15 min.)
E 10-8|
Journal |
||||
|
DATE |
ACCOUNT TITLES AND EXPLANATION |
DEBIT |
CREDIT |
|
|
Year |
15 |
Depreciation Expense |
||
|
[($775,000 ! $100,000) ) 40] |
16,875 |
|||
|
Accumulated Depreciation—Building |
16,875 |
|||
|
Year |
16 |
Depreciation Expense |
21,458* |
|
|
Accumulated Depreciation—Building |
21,458 |
|||
__________
*Computation:
Depreciable cost: $775,000
! $100,000 = $675,000Depreciation through year 15: $675,000
) 40 = $16,875 ´ 15 = $253,125Asset’s remaining depreciable book value:
$775,000
! $253,125 ! $200,000 = $321,875New estimated useful life remaining: 15 years
New annual depreciation: $321,875
) 15 = $21,458
(10-15 min.)
E 10-9|
Journal |
|||||
|
DATE |
ACCOUNTS AND EXPLANATIONS |
POST. REF. |
DEBIT |
CREDIT |
|
|
20X4 |
Depreciation for 9 months: |
||||
|
Sept. |
30 |
Depreciation Expense |
1,710a |
||
|
Accumulated Depreciation— |
|||||
|
Fixtures |
1,710 |
||||
|
|
|||||
|
Sale of fixtures: |
|||||
|
30 |
Cash |
4,950 |
|||
|
Accumulated Depreciation— |
|||||
|
Fixtures ($3,800 + $1,710) |
5,510 |
||||
|
Store Fixtures |
9,500 |
||||
|
Gain on Sale of Fixtures |
960b |
||||
__________
a
20X3 depreciation: $9,500 ´ 2/5 = $3,80020X4 depreciation: ($9,500
! $3,800) ´ 2/5 ´ 9/12 = $1,710
b
Gain is computed as follows:Sale price of old store fixtures........................... $4,950
Book value of old fixtures:
Cost............................................................... $9,500
Less Accumulated depreciation.................... (5,510) 3,990
Gain on sale....................................................... $ 960
(10-15 min.)
E 10-10Cost of new truck = Book value of old truck + Cash paid
$338,175 = $258,175a + $80,000
__________
a
Cost of old truck $385,000Accumulated depreciation:
|
($385,000 ! $100,000) ´ |
75 + 120 + 210 + 40 |
................. (126,825) |
|
1,000 |
_______
Book value of old truck $258,175
(10-15 min.)
E 10-11|
Journal |
|||||
|
DATE |
ACCOUNTS AND EXPLANATIONS |
POST. REF. |
DEBIT |
CREDIT |
|
|
(a) |
Purchase of minerals: |
||||
|
Mineral Asset |
298,500 |
||||
|
Cash |
298,500 |
||||
|
(b) |
Payment of fees and other costs: |
||||
|
Mineral Asset ($500 + $1,000) |
1,500 |
||||
|
Cash |
1,500 |
||||
|
Mineral Asset |
60,000 |
||||
|
Cash |
60,000 |
||||
|
(c) |
Depletion Expense |
75,600* |
|||
|
Accumulated Depletion— |
|||||
|
Mineral Asset |
75,600 |
||||
__________
*$298,500 + $500 + $1,000 + $60,000 = $360,000;
$360,000 ) 200,000 tons = $1.80 per ton;
42,000 tons ´ $1.80 = $75,600
(10-15 min.)
E 10-12|
Journal |
|||||
|
DATE |
ACCOUNTS AND EXPLANATIONS |
POST. REF. |
DEBIT |
CREDIT |
|
|
Part |
1(a) |
Purchase of patent: |
|||
|
Patents |
1,370,000 |
||||
|
Cash |
1,370,000 |
||||
|
(b) |
Amortization for one year: |
||||
|
Amortization Expense—Patents |
|||||
|
($1,370,000 ) 8) |
171,250 |
||||
|
Patents |
171,250 |
||||
|
Part |
2 |
Amortization for year 5: |
|||
|
Amortization Expense—Patents |
342,500* |
||||
|
Patents |
342,500 |
||||
__________
*Asset remaining book value: $1,370,000 ! ($171,250 ´ 4) = $685,000
New estimated useful life remaining: 2 years
New annual amortization: $685,000 ) 2 = $342,500
(10-15 min.)
E 10-13Req. 1
Campbell’s title
for goodwill: Purchase Price in Excess of Net Assets
of Businesses Acquired
This title fits the definition of goodwill almost word for word.
Req. 2
|
Millions |
|
|
Payments to acquire other businesses....................................... |
$105 |
|
Less: Payments for goodwill, included in |
|
|
the above purchase price ($1,697 ! $1,655)........................ |
(42 ) |
|
Payment for other assets, such as |
|
|
receivables, inventory, property, and equipment................. |
$ 63 |
(10-15 min.)
E 10-14Req. 1
Cost of goodwill purchased:
|
Purchase price paid for Adelaide Bakeries............................. |
$12,000,000 |
|
|
Market value of Adelaide’s net assets: |
||
|
Market value of Adelaide’s assets………... |
$15,000,000 |
|
|
Less: Adelaide’s liabilities.............………. |
(10,000,000) |
|
|
Market value of Adelaide’s net assets..................……….. |
5,000,000 |
|
|
Cost of goodwill purchased.................................................... |
$ 7,000,000 |
|
Reqs. 2 and 3
|
Journal |
|||||
|
DATE |
ACCOUNTS AND EXPLANATIONS |
POST. REF. |
DEBIT |
CREDIT |
|
|
Assets (Cash, Receivables, |
|||||
|
Inventories, Plant Assets) |
15,000,000 |
||||
|
Goodwill |
7,000,000 |
||||
|
Liabilities |
10,000,000 |
||||
|
Cash |
12,000,000 |
||||
|
Purchased Adelaide Bakeries. |
|||||
|
Amortization Expense— |
|||||
|
Goodwill ($7,000,000 ) 10) |
700,000 |
||||
|
Goodwill |
700,000 |
||||
|
Recorded amortization of goodwill. |
|||||
(15-20 min.)
E 10-15|
Year |
||||||
|
1 |
2 |
3 |
4 |
5 |
||
|
Millions of Francs (F) |
||||||
|
1. |
Total current assets |
No effects |
||||
|
2. |
Equipment, net |
F3.6u* |
F2.7u** |
F1.8u |
F0.9u |
Correct |
|
3. |
Net income |
3.6u* |
0.9o |
0.9o |
0.9o |
0.9o |
__________
u = Understated
o = Overstated
*Cost (F4.5 million)
! Depreciation expense (F.9 million) = F3.6 million**Cost (F4.5 million)
! Two years’ depreciation (F1.8 million) = F2.7million
(15-30 min.)
E 10-16(All amounts in millions of dollars)
Req. 1
|
Unamortized Special Tools |
|||
|
Dec. 31, 19X8 Balance |
7,298 |
||
|
19X9 Acquisitions |
2,559 |
19X9 Amortization |
2,492 |
|
Dec. 31, 19X9 Balance |
7,365 |
||
Req. 2
Sale proceeds ................................ $215
Less gain........................................ (15)
Book value of assets sold ............... $200