E 10-6

 

Depreciation Expense Per Year

Year

Straight-Line

Units-of-Production

Double-Declining-Balance

20X1

$ 3,000

$ 4,080

$ 7,500

20X2

3,000

3,360

3,750

20X3

3,000

2,160

375

20X4

3,000

2,400

375

 

 

$12,000

$12,000

$12,000

__________

Computations:

Straight-line: ($15,000 ! $3,000) ) 4 = $3,000 per year.

Units-of-production: ($15,000 ! $3,000) ) 100,000 miles = $.12 per mile;

34,000 ´ $.12 = $4,080; 28,000 ´ $.12 = $3,360; 18,000 ´ $.12 = $2,160;

20,000 ´ $.12 = $2,400.

Double-declining-balance: $15,000 ´ (1/4 ´ 2) = $7,500;

($15,000 ! $7,500) ´ 2/4 = $3,750; ($15,000 ! $7,500 ! $3,750) =

$3,750 ! $3,000 residual value = $750 ) 2 = $375.

The units-of-production method tracks the wear and tear on the truck most closely.

For income-tax purposes, the double-declining-balance method is best because it provides the most depreciation and thus the largest tax deductions in the early life of the asset. The company can invest the tax savings to earn a return on the investment.

 

(15-20 min.) E 10-7

MACRS depreciation method for income tax:

Double-declining-balance

 

 

 

Double-

Declining-

Balance

 

Straight-

Line

Year 1:

 

 

 

 

$165,000 ´ 2/7

$47,143

 

 

($165,000 ! $16,500) ) 7

 

 

$21,214

Year 2:

 

 

 

 

($165,000 ! $47,143) ´ 2/7

33,673

 

 

($165,000 ! $16,500) ) 7

______

21,214

Total

$80,816

$42,428

Extra cash to invest with DDB

 

 

 

 

($80,816 ! $42,428)

$38,388

 

__________

Note: This solution ignores the half-year convention of MACRS depreciation.

 

(10-15 min.) E 10-8

 

Journal

DATE

ACCOUNT TITLES AND EXPLANATION

DEBIT

CREDIT

Year

15

Depreciation Expense

   
   

[($775,000 ! $100,000) ) 40]

16,875

 
   

Accumulated Depreciation—Building

 

16,875

         

Year

16

Depreciation Expense

21,458*

 
   

Accumulated Depreciation—Building

 

21,458

__________

*Computation:

Depreciable cost: $775,000 ! $100,000 = $675,000

Depreciation through year 15: $675,000 ) 40 = $16,875 ´ 15 = $253,125

Asset’s remaining depreciable book value:

$775,000 ! $253,125 ! $200,000 = $321,875

New estimated useful life remaining: 15 years

New annual depreciation: $321,875 ) 15 = $21,458

 

(10-15 min.) E 10-9

Journal

DATE

ACCOUNTS AND EXPLANATIONS

POST.

REF.

DEBIT

CREDIT

20X4

Depreciation for 9 months:

     

Sept.

30

Depreciation Expense

 

1,710a

 
   

Accumulated Depreciation—

     
   

Fixtures

   

1,710

   

     
   

Sale of fixtures:

     
 

30

Cash

 

4,950

 
   

Accumulated Depreciation—

     
   

Fixtures ($3,800 + $1,710)

 

5,510

 
   

Store Fixtures

   

9,500

   

Gain on Sale of Fixtures

   

960b

__________

a20X3 depreciation: $9,500 ´ 2/5 = $3,800

20X4 depreciation: ($9,500 ! $3,800) ´ 2/5 ´ 9/12 = $1,710

 

bGain is computed as follows:

Sale price of old store fixtures........................... $4,950

Book value of old fixtures:

Cost............................................................... $9,500

Less Accumulated depreciation.................... (5,510) 3,990

Gain on sale....................................................... $ 960

(10-15 min.) E 10-10

Cost of new truck = Book value of old truck + Cash paid

$338,175 = $258,175a + $80,000

__________

aCost of old truck $385,000

Accumulated depreciation:

($385,000 ! $100,000) ´

75 + 120 + 210 + 40

................. (126,825)

1,000

_______

Book value of old truck $258,175

(10-15 min.) E 10-11

Journal

DATE

ACCOUNTS AND EXPLANATIONS

POST.

REF.

DEBIT

CREDIT

 

(a)

Purchase of minerals:

     
   

Mineral Asset

 

298,500

 
   

Cash

   

298,500

           
 

(b)

Payment of fees and other costs:

     
   

Mineral Asset ($500 + $1,000)

 

1,500

 
   

Cash

   

1,500

           
   

Mineral Asset

 

60,000

 
   

Cash

   

60,000

           
 

(c)

Depletion Expense

 

75,600*

 
   

Accumulated Depletion—

     
   

Mineral Asset

   

75,600

__________

*$298,500 + $500 + $1,000 + $60,000 = $360,000;

$360,000 ) 200,000 tons = $1.80 per ton;

42,000 tons ´ $1.80 = $75,600

 

(10-15 min.) E 10-12

Journal

DATE

ACCOUNTS AND EXPLANATIONS

POST.

REF.

DEBIT

CREDIT

Part

1(a)

Purchase of patent:

     
   

Patents

 

1,370,000

 
   

Cash

   

1,370,000

           
 

(b)

Amortization for one year:

     
   

Amortization Expense—Patents

     
   

($1,370,000 ) 8)

 

171,250

 
   

Patents

   

171,250

           

Part

2

Amortization for year 5:

     
   

Amortization Expense—Patents

 

342,500*

 
   

Patents

   

342,500

__________

*Asset remaining book value: $1,370,000 ! ($171,250 ´ 4) = $685,000

New estimated useful life remaining: 2 years

New annual amortization: $685,000 ) 2 = $342,500

 

(10-15 min.) E 10-13

Req. 1

Campbell’s title

for goodwill: Purchase Price in Excess of Net Assets

of Businesses Acquired

This title fits the definition of goodwill almost word for word.

 

Req. 2

 

Millions

Payments to acquire other businesses.......................................

$105

Less: Payments for goodwill, included in

 

the above purchase price ($1,697 ! $1,655)........................

(42)

Payment for other assets, such as

 

receivables, inventory, property, and equipment.................

$ 63

(10-15 min.) E 10-14

Req. 1

Cost of goodwill purchased:

Purchase price paid for Adelaide Bakeries.............................

$12,000,000

Market value of Adelaide’s net assets:

Market value of Adelaide’s assets………...

$15,000,000

Less: Adelaide’s liabilities.............……….

(10,000,000)

Market value of Adelaide’s net assets..................………..

5,000,000

Cost of goodwill purchased....................................................

$ 7,000,000

 

Reqs. 2 and 3

Journal

DATE

ACCOUNTS AND EXPLANATIONS

POST.

REF.

DEBIT

CREDIT

   

Assets (Cash, Receivables,

     
   

Inventories, Plant Assets)

 

15,000,000

 
   

Goodwill

 

7,000,000

 
   

Liabilities

   

10,000,000

   

Cash

   

12,000,000

   

Purchased Adelaide Bakeries.

     
           
   

Amortization Expense—

     
   

Goodwill ($7,000,000 ) 10)

 

700,000

 
   

Goodwill

   

700,000

   

Recorded amortization of goodwill.

     

 

(15-20 min.) E 10-15

 

Year

 

1

2

3

4

5

 

Millions of Francs (F)

1.

Total current assets

No effects

2.

Equipment, net

F3.6u*

F2.7u**

F1.8u

F0.9u

Correct

3.

Net income

3.6u*

0.9o

0.9o

0.9o

0.9o

__________

u = Understated

o = Overstated

*Cost (F4.5 million) ! Depreciation expense (F.9 million) = F3.6 million

**Cost (F4.5 million) ! Two years’ depreciation (F1.8 million) = F2.7

million

(15-30 min.) E 10-16

(All amounts in millions of dollars)

Req. 1

Unamortized Special Tools

Dec. 31, 19X8 Balance

7,298

   

19X9 Acquisitions

2,559

19X9 Amortization

2,492

       

Dec. 31, 19X9 Balance

7,365

   

 

Req. 2

Sale proceeds ................................ $215

Less gain........................................ (15)

Book value of assets sold ............... $200

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